Design of Column
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Column design |
Working Stress Method<
Slenderness ratio (λ)
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If λ > 12 then the column is long.
Load carrying capacity for short column
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where, AC = Area of concrete, 
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σSC Stress in compression steel
σCC Stress in concrete
Ag Total gross cross-sectional area
ASC Area of compression steel
Load carrying capacity for long column
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where,
Cr = Reduction factor
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where, leff = Effective length of column
B = Least lateral dimension
imin = Least radius of gyration and 
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where, l = Moment of inertia and A = Cross-sectional area
Effective length of column
Effective length of Compression Members
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Column with helical reinforcement
Strength of the column is increased by 5%
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Longitudinal reinforcement
(a) Minimum area of steel = 0.8% of the gross area of column
(b) Maximum area of steel
(i) When bars are not lapped Amax = 6% of the gross area of column
(ii) When bars are lapped Amax = 4% of the gross area of column
Minimum number of bars for reinforcement
For rectangular column 4
For circular column 6
Minimum diameter of bar = 12 mm
Maximum distance between longitudinal bar = 300 mm
Pedestal: It is a short length whose effective length is not more than 3 times of lest lateral dimension.
Transverse reinforcement (Ties)
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where
dia of main logitudnal bar
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φ = dia of bar for transverse reinforcement
Pitch (p)
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where, φmin = minimum dia of main longitudinal bar
Helical reinforcement
(i) Diameters of helical reinforcement is selected such that
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(ii) Pitch of helical reinforcement: (p)
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where,
dC = Core diameter = dg – 2 × clear cover to helical reinforcement
AG = Gross area 
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dg = Gross diameter
Vh = Volume of helical reinforcement in unit length of column
φh = Diameter of steel bar forming the helix
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dh = centre to centre dia of helix
= dg – 2 clear cover - φh
φh = diameter of the steel bar forming the helix
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Some others IS recommendations
(a) Slenderness limit
- Unsupported length between end restrains
60 times least lateral dimension.
- If in any given plane one end of column is unrestrained than its unsupported lengthAll column should be designed for a minimum eccentricity of
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Limit state method
- Slenderness ratio (λ)
if
λ<12 Short column
- Eccentricity
Ifthen it is a short axially loaded column.
where, Pu = axial load on the column - Short axially loaded column with helical reinforcement
- Some others IS code Recommendations
(a) Slenderness limit
(i) Unsupported length between end restrains
60 times least lateral dimension.
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(ii) If in any given plane one end of column is unrestrained than its unsupported length
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(b) All column should be designed for a minimum eccentricity of
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Concentrically Loaded Columns
Where e = 0, i.e., the column is truly axially loaded.
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This formula is also used for member subjected to combined axial load and bi- axial bending and also used when e > 0.05 D.
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